(2x^2+15x+29)/(x+4)

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Solution for (2x^2+15x+29)/(x+4) equation: 


D( x )

x+4 = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x in (-oo:-4) U (-4:+oo)

(2*x^2+15*x+29)/(x+4) = 0

2*x^2+15*x+29 = 0

2*x^2+15*x+29 = 0

DELTA = 15^2-(2*4*29)

DELTA = -7

DELTA < 0

1 = 0

1/(x+4) = 0

x belongs to the empty set

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